Integrand size = 20, antiderivative size = 141 \[ \int \frac {(A+B x) \left (a+b x^2\right )^{5/2}}{x^3} \, dx=\frac {5}{8} a b (4 A+3 B x) \sqrt {a+b x^2}-\frac {5 (3 a B-2 A b x) \left (a+b x^2\right )^{3/2}}{12 x}-\frac {(2 A-B x) \left (a+b x^2\right )^{5/2}}{4 x^2}+\frac {15}{8} a^2 \sqrt {b} B \text {arctanh}\left (\frac {\sqrt {b} x}{\sqrt {a+b x^2}}\right )-\frac {5}{2} a^{3/2} A b \text {arctanh}\left (\frac {\sqrt {a+b x^2}}{\sqrt {a}}\right ) \]
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Time = 0.08 (sec) , antiderivative size = 141, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {827, 829, 858, 223, 212, 272, 65, 214} \[ \int \frac {(A+B x) \left (a+b x^2\right )^{5/2}}{x^3} \, dx=-\frac {5}{2} a^{3/2} A b \text {arctanh}\left (\frac {\sqrt {a+b x^2}}{\sqrt {a}}\right )+\frac {15}{8} a^2 \sqrt {b} B \text {arctanh}\left (\frac {\sqrt {b} x}{\sqrt {a+b x^2}}\right )-\frac {\left (a+b x^2\right )^{5/2} (2 A-B x)}{4 x^2}-\frac {5 \left (a+b x^2\right )^{3/2} (3 a B-2 A b x)}{12 x}+\frac {5}{8} a b \sqrt {a+b x^2} (4 A+3 B x) \]
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Rule 65
Rule 212
Rule 214
Rule 223
Rule 272
Rule 827
Rule 829
Rule 858
Rubi steps \begin{align*} \text {integral}& = -\frac {(2 A-B x) \left (a+b x^2\right )^{5/2}}{4 x^2}-\frac {5}{16} \int \frac {(-4 a B-8 A b x) \left (a+b x^2\right )^{3/2}}{x^2} \, dx \\ & = -\frac {5 (3 a B-2 A b x) \left (a+b x^2\right )^{3/2}}{12 x}-\frac {(2 A-B x) \left (a+b x^2\right )^{5/2}}{4 x^2}+\frac {5}{32} \int \frac {(16 a A b+24 a b B x) \sqrt {a+b x^2}}{x} \, dx \\ & = \frac {5}{8} a b (4 A+3 B x) \sqrt {a+b x^2}-\frac {5 (3 a B-2 A b x) \left (a+b x^2\right )^{3/2}}{12 x}-\frac {(2 A-B x) \left (a+b x^2\right )^{5/2}}{4 x^2}+\frac {5 \int \frac {32 a^2 A b^2+24 a^2 b^2 B x}{x \sqrt {a+b x^2}} \, dx}{64 b} \\ & = \frac {5}{8} a b (4 A+3 B x) \sqrt {a+b x^2}-\frac {5 (3 a B-2 A b x) \left (a+b x^2\right )^{3/2}}{12 x}-\frac {(2 A-B x) \left (a+b x^2\right )^{5/2}}{4 x^2}+\frac {1}{2} \left (5 a^2 A b\right ) \int \frac {1}{x \sqrt {a+b x^2}} \, dx+\frac {1}{8} \left (15 a^2 b B\right ) \int \frac {1}{\sqrt {a+b x^2}} \, dx \\ & = \frac {5}{8} a b (4 A+3 B x) \sqrt {a+b x^2}-\frac {5 (3 a B-2 A b x) \left (a+b x^2\right )^{3/2}}{12 x}-\frac {(2 A-B x) \left (a+b x^2\right )^{5/2}}{4 x^2}+\frac {1}{4} \left (5 a^2 A b\right ) \text {Subst}\left (\int \frac {1}{x \sqrt {a+b x}} \, dx,x,x^2\right )+\frac {1}{8} \left (15 a^2 b B\right ) \text {Subst}\left (\int \frac {1}{1-b x^2} \, dx,x,\frac {x}{\sqrt {a+b x^2}}\right ) \\ & = \frac {5}{8} a b (4 A+3 B x) \sqrt {a+b x^2}-\frac {5 (3 a B-2 A b x) \left (a+b x^2\right )^{3/2}}{12 x}-\frac {(2 A-B x) \left (a+b x^2\right )^{5/2}}{4 x^2}+\frac {15}{8} a^2 \sqrt {b} B \tanh ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a+b x^2}}\right )+\frac {1}{2} \left (5 a^2 A\right ) \text {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b x^2}\right ) \\ & = \frac {5}{8} a b (4 A+3 B x) \sqrt {a+b x^2}-\frac {5 (3 a B-2 A b x) \left (a+b x^2\right )^{3/2}}{12 x}-\frac {(2 A-B x) \left (a+b x^2\right )^{5/2}}{4 x^2}+\frac {15}{8} a^2 \sqrt {b} B \tanh ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a+b x^2}}\right )-\frac {5}{2} a^{3/2} A b \tanh ^{-1}\left (\frac {\sqrt {a+b x^2}}{\sqrt {a}}\right ) \\ \end{align*}
Time = 0.45 (sec) , antiderivative size = 132, normalized size of antiderivative = 0.94 \[ \int \frac {(A+B x) \left (a+b x^2\right )^{5/2}}{x^3} \, dx=5 a^{3/2} A b \text {arctanh}\left (\frac {\sqrt {b} x-\sqrt {a+b x^2}}{\sqrt {a}}\right )+\frac {1}{24} \left (\frac {\sqrt {a+b x^2} \left (-12 a^2 (A+2 B x)+2 b^2 x^4 (4 A+3 B x)+a b x^2 (56 A+27 B x)\right )}{x^2}-45 a^2 \sqrt {b} B \log \left (-\sqrt {b} x+\sqrt {a+b x^2}\right )\right ) \]
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Time = 3.39 (sec) , antiderivative size = 145, normalized size of antiderivative = 1.03
method | result | size |
risch | \(-\frac {a^{2} \sqrt {b \,x^{2}+a}\, \left (2 B x +A \right )}{2 x^{2}}+\frac {15 \sqrt {b}\, a^{2} B \ln \left (x \sqrt {b}+\sqrt {b \,x^{2}+a}\right )}{8}+\frac {B \,b^{2} x^{3} \sqrt {b \,x^{2}+a}}{4}+\frac {9 B b a x \sqrt {b \,x^{2}+a}}{8}+\frac {b^{2} A \,x^{2} \sqrt {b \,x^{2}+a}}{3}+\frac {7 b A a \sqrt {b \,x^{2}+a}}{3}-\frac {5 b \,a^{\frac {3}{2}} A \ln \left (\frac {2 a +2 \sqrt {a}\, \sqrt {b \,x^{2}+a}}{x}\right )}{2}\) | \(145\) |
default | \(B \left (-\frac {\left (b \,x^{2}+a \right )^{\frac {7}{2}}}{a x}+\frac {6 b \left (\frac {x \left (b \,x^{2}+a \right )^{\frac {5}{2}}}{6}+\frac {5 a \left (\frac {x \left (b \,x^{2}+a \right )^{\frac {3}{2}}}{4}+\frac {3 a \left (\frac {x \sqrt {b \,x^{2}+a}}{2}+\frac {a \ln \left (x \sqrt {b}+\sqrt {b \,x^{2}+a}\right )}{2 \sqrt {b}}\right )}{4}\right )}{6}\right )}{a}\right )+A \left (-\frac {\left (b \,x^{2}+a \right )^{\frac {7}{2}}}{2 a \,x^{2}}+\frac {5 b \left (\frac {\left (b \,x^{2}+a \right )^{\frac {5}{2}}}{5}+a \left (\frac {\left (b \,x^{2}+a \right )^{\frac {3}{2}}}{3}+a \left (\sqrt {b \,x^{2}+a}-\sqrt {a}\, \ln \left (\frac {2 a +2 \sqrt {a}\, \sqrt {b \,x^{2}+a}}{x}\right )\right )\right )\right )}{2 a}\right )\) | \(187\) |
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Time = 0.32 (sec) , antiderivative size = 535, normalized size of antiderivative = 3.79 \[ \int \frac {(A+B x) \left (a+b x^2\right )^{5/2}}{x^3} \, dx=\left [\frac {45 \, B a^{2} \sqrt {b} x^{2} \log \left (-2 \, b x^{2} - 2 \, \sqrt {b x^{2} + a} \sqrt {b} x - a\right ) + 60 \, A a^{\frac {3}{2}} b x^{2} \log \left (-\frac {b x^{2} - 2 \, \sqrt {b x^{2} + a} \sqrt {a} + 2 \, a}{x^{2}}\right ) + 2 \, {\left (6 \, B b^{2} x^{5} + 8 \, A b^{2} x^{4} + 27 \, B a b x^{3} + 56 \, A a b x^{2} - 24 \, B a^{2} x - 12 \, A a^{2}\right )} \sqrt {b x^{2} + a}}{48 \, x^{2}}, -\frac {45 \, B a^{2} \sqrt {-b} x^{2} \arctan \left (\frac {\sqrt {-b} x}{\sqrt {b x^{2} + a}}\right ) - 30 \, A a^{\frac {3}{2}} b x^{2} \log \left (-\frac {b x^{2} - 2 \, \sqrt {b x^{2} + a} \sqrt {a} + 2 \, a}{x^{2}}\right ) - {\left (6 \, B b^{2} x^{5} + 8 \, A b^{2} x^{4} + 27 \, B a b x^{3} + 56 \, A a b x^{2} - 24 \, B a^{2} x - 12 \, A a^{2}\right )} \sqrt {b x^{2} + a}}{24 \, x^{2}}, \frac {120 \, A \sqrt {-a} a b x^{2} \arctan \left (\frac {\sqrt {-a}}{\sqrt {b x^{2} + a}}\right ) + 45 \, B a^{2} \sqrt {b} x^{2} \log \left (-2 \, b x^{2} - 2 \, \sqrt {b x^{2} + a} \sqrt {b} x - a\right ) + 2 \, {\left (6 \, B b^{2} x^{5} + 8 \, A b^{2} x^{4} + 27 \, B a b x^{3} + 56 \, A a b x^{2} - 24 \, B a^{2} x - 12 \, A a^{2}\right )} \sqrt {b x^{2} + a}}{48 \, x^{2}}, -\frac {45 \, B a^{2} \sqrt {-b} x^{2} \arctan \left (\frac {\sqrt {-b} x}{\sqrt {b x^{2} + a}}\right ) - 60 \, A \sqrt {-a} a b x^{2} \arctan \left (\frac {\sqrt {-a}}{\sqrt {b x^{2} + a}}\right ) - {\left (6 \, B b^{2} x^{5} + 8 \, A b^{2} x^{4} + 27 \, B a b x^{3} + 56 \, A a b x^{2} - 24 \, B a^{2} x - 12 \, A a^{2}\right )} \sqrt {b x^{2} + a}}{24 \, x^{2}}\right ] \]
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Time = 3.21 (sec) , antiderivative size = 381, normalized size of antiderivative = 2.70 \[ \int \frac {(A+B x) \left (a+b x^2\right )^{5/2}}{x^3} \, dx=- \frac {5 A a^{\frac {3}{2}} b \operatorname {asinh}{\left (\frac {\sqrt {a}}{\sqrt {b} x} \right )}}{2} - \frac {A a^{2} \sqrt {b} \sqrt {\frac {a}{b x^{2}} + 1}}{2 x} + \frac {2 A a^{2} \sqrt {b}}{x \sqrt {\frac {a}{b x^{2}} + 1}} + \frac {2 A a b^{\frac {3}{2}} x}{\sqrt {\frac {a}{b x^{2}} + 1}} + A b^{2} \left (\begin {cases} \frac {a \sqrt {a + b x^{2}}}{3 b} + \frac {x^{2} \sqrt {a + b x^{2}}}{3} & \text {for}\: b \neq 0 \\\frac {\sqrt {a} x^{2}}{2} & \text {otherwise} \end {cases}\right ) - \frac {B a^{\frac {5}{2}}}{x \sqrt {1 + \frac {b x^{2}}{a}}} - \frac {B a^{\frac {3}{2}} b x}{\sqrt {1 + \frac {b x^{2}}{a}}} + B a^{2} \sqrt {b} \operatorname {asinh}{\left (\frac {\sqrt {b} x}{\sqrt {a}} \right )} + 2 B a b \left (\begin {cases} \frac {a \left (\begin {cases} \frac {\log {\left (2 \sqrt {b} \sqrt {a + b x^{2}} + 2 b x \right )}}{\sqrt {b}} & \text {for}\: a \neq 0 \\\frac {x \log {\left (x \right )}}{\sqrt {b x^{2}}} & \text {otherwise} \end {cases}\right )}{2} + \frac {x \sqrt {a + b x^{2}}}{2} & \text {for}\: b \neq 0 \\\sqrt {a} x & \text {otherwise} \end {cases}\right ) + B b^{2} \left (\begin {cases} - \frac {a^{2} \left (\begin {cases} \frac {\log {\left (2 \sqrt {b} \sqrt {a + b x^{2}} + 2 b x \right )}}{\sqrt {b}} & \text {for}\: a \neq 0 \\\frac {x \log {\left (x \right )}}{\sqrt {b x^{2}}} & \text {otherwise} \end {cases}\right )}{8 b} + \frac {a x \sqrt {a + b x^{2}}}{8 b} + \frac {x^{3} \sqrt {a + b x^{2}}}{4} & \text {for}\: b \neq 0 \\\frac {\sqrt {a} x^{3}}{3} & \text {otherwise} \end {cases}\right ) \]
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Time = 0.20 (sec) , antiderivative size = 143, normalized size of antiderivative = 1.01 \[ \int \frac {(A+B x) \left (a+b x^2\right )^{5/2}}{x^3} \, dx=\frac {5}{4} \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} B b x + \frac {15}{8} \, \sqrt {b x^{2} + a} B a b x + \frac {15}{8} \, B a^{2} \sqrt {b} \operatorname {arsinh}\left (\frac {b x}{\sqrt {a b}}\right ) - \frac {5}{2} \, A a^{\frac {3}{2}} b \operatorname {arsinh}\left (\frac {a}{\sqrt {a b} {\left | x \right |}}\right ) + \frac {5}{6} \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} A b + \frac {{\left (b x^{2} + a\right )}^{\frac {5}{2}} A b}{2 \, a} + \frac {5}{2} \, \sqrt {b x^{2} + a} A a b - \frac {{\left (b x^{2} + a\right )}^{\frac {5}{2}} B}{x} - \frac {{\left (b x^{2} + a\right )}^{\frac {7}{2}} A}{2 \, a x^{2}} \]
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Time = 0.32 (sec) , antiderivative size = 219, normalized size of antiderivative = 1.55 \[ \int \frac {(A+B x) \left (a+b x^2\right )^{5/2}}{x^3} \, dx=\frac {5 \, A a^{2} b \arctan \left (-\frac {\sqrt {b} x - \sqrt {b x^{2} + a}}{\sqrt {-a}}\right )}{\sqrt {-a}} - \frac {15}{8} \, B a^{2} \sqrt {b} \log \left ({\left | -\sqrt {b} x + \sqrt {b x^{2} + a} \right |}\right ) + \frac {1}{24} \, {\left (56 \, A a b + {\left (27 \, B a b + 2 \, {\left (3 \, B b^{2} x + 4 \, A b^{2}\right )} x\right )} x\right )} \sqrt {b x^{2} + a} + \frac {{\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{3} A a^{2} b + 2 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{2} B a^{3} \sqrt {b} + {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )} A a^{3} b - 2 \, B a^{4} \sqrt {b}}{{\left ({\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{2} - a\right )}^{2}} \]
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Time = 7.04 (sec) , antiderivative size = 111, normalized size of antiderivative = 0.79 \[ \int \frac {(A+B x) \left (a+b x^2\right )^{5/2}}{x^3} \, dx=\frac {A\,b\,{\left (b\,x^2+a\right )}^{3/2}}{3}+2\,A\,a\,b\,\sqrt {b\,x^2+a}-\frac {A\,a^2\,\sqrt {b\,x^2+a}}{2\,x^2}-\frac {B\,{\left (b\,x^2+a\right )}^{5/2}\,{{}}_2{\mathrm {F}}_1\left (-\frac {5}{2},-\frac {1}{2};\ \frac {1}{2};\ -\frac {b\,x^2}{a}\right )}{x\,{\left (\frac {b\,x^2}{a}+1\right )}^{5/2}}+\frac {A\,a^{3/2}\,b\,\mathrm {atan}\left (\frac {\sqrt {b\,x^2+a}\,1{}\mathrm {i}}{\sqrt {a}}\right )\,5{}\mathrm {i}}{2} \]
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